Friday

March 6, 2015

March 6, 2015

Posted by **Physics/Math** on Friday, February 23, 2007 at 2:47am.

Integrate the force vs time function during the period of contact. This will tell you the momentum delivered to the ball.

Impulse = Integral of a t- b t^2

from t = 0 to t = 2*10^-3 s,

where

a = 5*10^6 and b = 2.5*10^9

The integral is at^2/2 - bt^3/3.

Evaluate it at the limits of integration and take the difference.

The average force is the impulse divided by the time of contact.

The maximum force occurs when f'(t) is zero, which is when

a = 2 b t

t = a/(2 b) = 1.0*10^-3 s.

The ball's velocity when it leaves the foot = (momentum change)/mass = (impulse)/mass

(since the initial momentum is zero)

Great...I got it. Thanks :)

**Answer this Question**

**Related Questions**

physics - A soccer ball with mass 0.410 kg is initially moving with speed 4.30 m...

science - A soccer player applies an average force of 180 N during a kick. The ...

physics - A 0.405 soccer ball is initially moving at 2.05. A soccer player kicks...

physics - A football, if it was kicked when initially at rest, is inflated such ...

physics - A 0.5 kg soccer ball is kicked with a force of 50 Newtons for 0.2 sec...

Physics - A soccer player kicks a ball into the air at an angle of 36.0 Degrees ...

Physics help - A soccer player kicks a soccer ball at +10.0 m/s at an angle of ...

physical science - A soccer player applies a force of 51.5 N to a soccer ball ...

Physics - A soccer player kicks a ball into the air at an angle of 36 degrees ...

physics - a soccer player kicks the ball exerting a force 45N on the ball.During...