maths, please help!
posted by elle on .
I need help solving this:
6x^2x12=0
I usually could do this yet i have completely forgotten what i need to do seeing as there is a number infront of the x^2
This equation is of the general form
a x^2 + bx + c = 0
The solution is always
x = [b +/ sqrt (b^2  4ac)]/(2a)
= [1 +/ sqrt (1 + 288)]/12
= [1 +/ 17)/12
= 3/2 or 4/3
The equation could also have been factored into
(2x  3)(3x + 4) = 0
14.
a)Write the prime factorization of 3600 using exponets
b)write the prime factorization of the square root of 3600

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