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December 20, 2014

December 20, 2014

Posted by **elle** on Thursday, February 22, 2007 at 5:30am.

6x^2-x-12=0

I usually could do this yet i have completely forgotten what i need to do seeing as there is a number infront of the x^2

This equation is of the general form

a x^2 + bx + c = 0

The solution is always

x = [-b +/- sqrt (b^2 - 4ac)]/(2a)

= [1 +/- sqrt (1 + 288)]/12

= [1 +/- 17)/12

= 3/2 or -4/3

The equation could also have been factored into

(2x - 3)(3x + 4) = 0

14.

a)Write the prime factorization of 3600 using exponets

b)write the prime factorization of the square root of 3600

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