Posted by
**winterWX** on
.

A 5.60-kg particle has the xy coordinates (-1.20 m, 0.500 m), and a 5.20-kg particle has the xy coordinates (0.600 m, -0.750 m). Both lie on a horizontal plane. At what x and y coordinates must you place a 1.60-kg particle such that the center of mass of the three-particle system has the coordinates (-0.500 , -0.700 m)?

(m1+m2+m2)(-.5)= 5.6(-1.2) + 5.2(.6) + 1.6(x) solve for x.

Do the same for y.