Thursday

July 24, 2014

July 24, 2014

Posted by **jessica** on Tuesday, February 20, 2007 at 9:22pm.

f(x) = ((3x-7)/(6x+3))^4

f '(x) =

let u= 3x-7

v= (6x+3)^-4

Then d(uv)= u dv + v du

du= 3 dv= -4(6x+3)^-5 (6)

so what's f'(x)? (thanks for your help)

Goodness. f'(x) is d(uv)

I will be happy to critique your work or thinking.

in the orginal problem, the entire thing is squared to the 4th power not just the denominator. and also, where and how did u change 4 to a -4?

I didn't see that. OK, change u to ((3x-7)^4 that changes du to 12(3x-7)^3

v= 1/(6x+3)^4= (6x+3)^-4

are u sure u change it to 12(3x-7)^3 and not 4(3x-7)^3?? i'm just curious. i'm trying to follow u but my derivative came out different from urs again.

**Related Questions**

MoRe HeLp PlEaSe!! (calc) - Also can I get some help with this LONG, TIRESOME ...

calculus - Please help. Applying the chain rule, how do I find the derivative of...

Calculus - How do I use the chain rule to find the derivative of square root(1-x...

CAlculus - using chain rule find the derivative of y=xsin1/x

Applied Calculus - Find the derivative of this function: g(t)=(8t+10)^2*(10t^2-7...

calculus-derivatives - y=cos^3(12theta) find derivative using chain rule

Calculus - find the derivative of f(x)=((x^2+3)^5+x)^2 using the chain rule. I ...

Calculus - Find the derivative: h(x)=7x/sqrt(5-2x) Using the chain rule...I ...

Math, Calculus - Find the derivative of the function. y= xcosx - sinx What's the...

calculus - let y=(x+sin(x))^2 f(x)=? g(x)=? (f o g)'=? compute the derivative ...