Homework Help: calculus

Posted by jessica on Tuesday, February 20, 2007 at 9:22pm.

Find the derivative using the chain rule.
f(x) = ((3x-7)/(6x+3))^4
f '(x) =

let u= 3x-7
v= (6x+3)^-4

Then d(uv)= u dv + v du

du= 3 dv= -4(6x+3)^-5 (6)

so what's f'(x)? (thanks for your help)

Goodness. f'(x) is d(uv)

I will be happy to critique your work or thinking.

in the orginal problem, the entire thing is squared to the 4th power not just the denominator. and also, where and how did u change 4 to a -4?

I didn't see that. OK, change u to ((3x-7)^4 that changes du to 12(3x-7)^3

v= 1/(6x+3)^4= (6x+3)^-4

are u sure u change it to 12(3x-7)^3 and not 4(3x-7)^3?? i'm just curious. i'm trying to follow u but my derivative came out different from urs again.

No one has answered this question yet.

Answer this Question

Related Questions

MoRe HeLp PlEaSe!! (calc) - Also can I get some help with this LONG, TIRESOME ...
derivative - 41) Find the derivative. h(x)= (3x^2 + 1)^3 / (x^2 - 1)^4 This is ...
Calculus (Help) - Also I would like to know how to set this problem up in ...
Math - Differentiate g(x)=(x^3+1)(3x^2-1) so I use g'(x) X h(x) + g(x) X h&#...
math - 3x-4=-2(3x+5) 3x-4=-2(3x+5) clear the fraction. 3x-4=-6x-10 add+6x+4 to ...
Algebra - checking problem Use FOIL to multiply: (6x – 1)(3x – 4) 6x*...
Math- Adv. Alg. w/ Trig. - I need help simplifying this expression: (3x^3y^5 + ...
Math - Can someone please check my answers below for accurateness? The ...
Calculus II - Integrate using integration by parts (integral) (5-x) e^3x u = 5-x...
Calc I - Find the range of y = (3x-1)/(2x^2 + x - 6) I was going to take the ...

For Further Reading

First Name:
School Subject:
Answer: