Wednesday

August 20, 2014

August 20, 2014

Posted by **jas20** on Tuesday, February 20, 2007 at 9:22pm.

Directions: Solve each of the following applications. Give all answers to the nearest thousandth.

Problem: Geometry. The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle?

Let x = width of rectangle

Let x + 1 = length of rectangle

Remember that a^2 + b^2 = c^2

Therefore:

x^2 + (x + 1)^2 = 4^2

Can you take it from here to solve for x?

Don't forget to include the length and the width in your answer.

- algebra , help -
**Jada**, Tuesday, July 9, 2013 at 5:51pmThe length of a rectangle is 2 more than 3 times the width , if the perimeter is 100 meters what is the width of the rectangle

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