Posted by **jas20** on Tuesday, February 20, 2007 at 9:22pm.

Can someone help me set up the equations thanks.

Directions: Solve each of the following applications. Give all answers to the nearest thousandth.

Problem: Geometry. The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle?

Let x = width of rectangle

Let x + 1 = length of rectangle

Remember that a^2 + b^2 = c^2

Therefore:

x^2 + (x + 1)^2 = 4^2

Can you take it from here to solve for x?

Don't forget to include the length and the width in your answer.

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