Wednesday

December 17, 2014

December 17, 2014

Posted by **drwls** on Tuesday, February 20, 2007 at 5:07am.

Use integration by parts.

Let sin x = u and sin x dx = dv

v = -cos x

du = cos x dx

The integral is u v - integral of v du

= -sinx cosx + integral of cos^2 dx

which can be rewritten

integral of sin^2 x = -sinx cos x + integral of (1 - sin^2) dx

2 * (integral of sin^2 x dx)

= - sin x cos x + integral of dx

integral of sin^2 dx = (-1/2) sin x cos x + x/2

integral of (1-cos^2 x) dx

might be easy but i need to make sure

**Answer this Question**

**Related Questions**

trig integration - i'm having trouble evaluating the integral at pi/2 and 0. i ...

trig integration - s- integral endpoints are 0 and pi/2 i need to find the ...

math - I'm trying to find the convolution f*g where f(t)=g(t)=sin(t). I set up ...

Math/Calculus - How would I integrate the following by parts: Integral of: (x^2...

Calculus Problem - I need to find the integral of e^(2x)sin(3x) I used ...

Calculus - Evaluate the integral. S= integral sign I= absolute value S ((cos x...

Calculus AP - Evaluate the integral interval from [0 to pi] t sin(3t)dt Use ...

calc - find integral using table of integrals ) integral sin^4xdx this the ...

algebra - Can someone please help me do this problem? That would be great! ...

tigonometry - expres the following as sums and differences of sines or cosines ...