Posted by **COFFEE** on Sunday, February 18, 2007 at 10:34pm.

At time t1 = 2.00 s, the acceleration of a particle in counterclockwise circular motion is (9.00i + 8.00j) m/s^2. It moves at constant speed. At time t2 = 3.00s (3/4 of a revolution later), it's acceleration is (8.00i - 9.00j) m/s^2. Find the radius of the path taken by the particle.

see below.

## Answer this Question

## Related Questions

- Physics/Math - At time t1 = 2.00 s, the acceleration of a particle in ...
- Physics College - Circular motion - At time t1 = 2.00 s, the acceleration of a ...
- Physics - A particle initially located at the origin has an acceleration of a= 5...
- physics - 1.Give examples of a one-dimensional motion where (a) the particle ...
- Physics - A 0.500 kg particle moves in a circle of R=0.0150 m at constant speed...
- Physics - Two forces act on a 0.200 kg ant: F1 =(3.00i - 8.00j)N and F2=(5.00i...
- physics - A particle moves along a circular path over a horizontal xy coordinate...
- Physics - A particle moves along a circular path over a horizontal xy coordinate...
- PHYSICS1 - A particle moves along a circular path over a horizontal xy ...
- math - Which three options are true about motion in a straight line. A. A ...

More Related Questions