Friday

January 30, 2015

January 30, 2015

Posted by **christine** on Sunday, February 18, 2007 at 1:49am.

endpoints are 0 and pi/2

i need to find the integral of sin^2 (2x) dx.

i know that the answer is pi/4, but im not sure how to get to it.

i know:

s sin^2(2x)dx= 1/2 [1-cos (4x)] dx, but then i'm confused.

The indefinite integral of

(1/2) [1-cos (4x)] is

(x/2) - (1/2)(1/4)(sin 4x)

Evaluate that at x = p/2 and 0 and take the difference

I get [(pi/4) -0] - {0 - 0) = pi/4

YOu got the hardest part, now expand your expression.

Hint: what is the derivative of 1/8 sin(4x)?

**Answer this Question**

**Related Questions**

Integral - That's the same as the integral of sin^2 x dx. Use integration by ...

trig integration - i'm having trouble evaluating the integral at pi/2 and 0. i ...

Integral Help - I need to find the integral of (sin x)/ cos^3 x I let u= cos x, ...

calc - find integral using table of integrals ) integral sin^4xdx this the ...

calculus - 1. integral -oo, oo [(2x)/(x^2+1)^2] dx 2. integral 0, pi/2 cot(theta...

double integral - 1. Sketch the region of integration & reverse the order of ...

math - I'm trying to find the convolution f*g where f(t)=g(t)=sin(t). I set up ...

integration by parts - s- integral s ln (2x+1)dx ? = ln(2x+1)x - s x d( ln (2x+1...

Calculus - I need help with this integral. w= the integral from 0 to 5 24e^-6t ...

calc - how do you start this problem: integral of xe^(-2x) There are two ways: 1...