Posted by **nicholas** on Saturday, February 17, 2007 at 9:01pm.

s- integral

s ln (2x+1)dx ?

= ln(2x+1)x - s x d( ln (2x+1))

= ln(2x+1)x- s x [(2x+1)'/ (2x+1)] dx

= ln(2x+1)x- s x [(2)/ (2x+1)] dx

= ln(2x+1)x- s (2x/2x+1) dx

= ln(2x+1)x- s [(2x+1-1)/(2x+1)] ... i'm confused about why there is a minus 1 after the integral

## Answer this Question

## Related Questions

- integration by parts - s- integral s ln (2x+1)dx ? = ln(2x+1)x - s x d( ln (2x+1...
- calc - evaluate the integral: y lny dy i know it's integration by parts but i ...
- Integration by Parts - integral from 0 to 2pi of isin(t)e^(it)dt. I know my ...
- Calculus II - Integrate using integration by parts (integral) (5-x) e^3x u = 5-x...
- Math - Indefinite Integration - Use integration by parts to solve: I = f (x^3)(e...
- calc - how do you start this problem: integral of xe^(-2x) There are two ways: 1...
- Calc 2 - a. Integral (x^2)/(sqrt(1+(x^2))) Would I separate these two into 2 ...
- Calculus II - Evaluate the integral using method of integration by parts: (...
- Integral - That's the same as the integral of sin^2 x dx. Use integration by ...
- calculus - How do you find: the Integral of arcsin(1 / (sqrt x^2 - 1) ) dx ?? (...

More Related Questions