Saturday
May 25, 2013

Homework Help: Chemistry

Posted by Bob on Saturday, February 17, 2007 at 8:15pm.

How many ml of a 0.827 Molar KOH solution is required for neutralization in a titration of 35.00 ml of 0.737 Molar H2SO4?

Write the equation.
2KOH + H2SO4 ==> 2H2O + K2SO4

mols H2SO4 = M x L = 0.03500 L x 0.737 M = ??

mols KOH = 2 x mols H2SO4 from the equation.

mols KOH = M x L. You know mols KOH, you know M, solve for L and change to mL.

62.4 ml

thanks

No one has answered this question yet.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Chemistry - In a titration of 35.00 mL of 0.737 M S, __________ mL of a 0.827 M ...
Chemistry - In a titration of 35.00 mL of 0.737 M S, __________ mL of a 0.827 M ...
Chemistry - In a titration of 26.0 mL of 0.840 M H2SO4, __________ mL of a 0.200...
Chemistry - In a titration experiment 34.12 mL of 0.902 M KOH is reacted with ...
chem - a.)How many moles of NaOH are required to prepare 2.00L od 0.380M ...
Chemistry - A 25.00-mL sample of an H2SO4 (2 and 4 are subscripted) solution of ...
Chemistry - A 25.00-mL sample of an H2SO4 (2 and 4 are subscripted) solution of ...
chemistry - Titration of 25.00 mL of KOH required 200.00 mL of 0.0050 M acetic ...
Chemistry - Determine the volume of 0.240 M KOH solution required to neutralize ...
Chemistry (repost) - Determine the volume of 0.240 M KOH solution required to ...

For Further Reading

Search
Members
Community