Posted by Bob on .
How many ml of a 0.827 Molar KOH solution is required for neutralization in a titration of 35.00 ml of 0.737 Molar H2SO4?
Write the equation.
2KOH + H2SO4 ==> 2H2O + K2SO4
mols H2SO4 = M x L = 0.03500 L x 0.737 M = ??
mols KOH = 2 x mols H2SO4 from the equation.
mols KOH = M x L. You know mols KOH, you know M, solve for L and change to mL.