Posted by
**Bob** on
.

How many ml of a 0.827 Molar KOH solution is required for neutralization in a titration of 35.00 ml of 0.737 Molar H2SO4?

Write the equation.

2KOH + H2SO4 ==> 2H2O + K2SO4

mols H2SO4 = M x L = 0.03500 L x 0.737 M = ??

mols KOH = 2 x mols H2SO4 from the equation.

mols KOH = M x L. You know mols KOH, you know M, solve for L and change to mL.

62.4 ml

thanks