Saturday

April 19, 2014

April 19, 2014

Posted by **bex** on Saturday, February 17, 2007 at 11:48am.

the info is drop of oil 0.05 cm3 from a dropper spreads out to 40 cm2

is it

vol = l x w x h

0.05cm3 = 20 x 20 xh

0.05 cm3 = 40cm2

after this im stuck as i dont know what the size of the oil molecule is

can anyone help

vol = l x w x h

0.05cm3 = 20 x 20 xh

0.05 cm3 = 40cm2

after this im stuck as i dont know what the size of the oil molecule is

can anyone help

You have 0.05 cc = lxwxh.

The problem states that the oil drop spreads out to an area of 40 cm

0.05 = 40*h

solve for h.

I think i have managed it

0.05cm3 = 40 x h

h = 0.05/ 40

h = 1.25 x 10-3cm3

is this correct please

im trying to help my daughter out on this i think i need to go back to school lol

Correct if you aren't worried about the number of significant figures. There are only two s.f. in 0.05 and two in 40 (if it is 40. and not 4 x 10^1); therefore, you are allowed only two in the answer and 1.25 has three. You must round it, if s.f. are a concern, to either 1.3 x 10^-3 or 1.2 x 10^-3 depending upon how your instructor has taught you to do it. I round to the EVEN number; therefore, I would round to 1.2 x 10^-3. A note about the 40. 40 with no decimal point after it has only one s.f., 40. has two. 4 x 10^1 has one. If the 40 has only one s.f., then 1 x 10^-3 is the answer.

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