Saturday

December 20, 2014

December 20, 2014

Posted by **Jen** on Saturday, February 17, 2007 at 10:01am.

How do I solve this graphically? Thanks.

Make a graph of e^(3 - 2x) vs x for various values of x from 0 to 2. The answer will be in that interval. Where the graph crosses f(x) = y = 4, read off the value of x. That will be the answer.

When x = 0, e^(3-2x)= e^3 = 20.09

When x = 0.5, e^(3-2x) = e^2 = 7.389

When x = 1, e^(3-2x)= e = 2.718

The answer f(x) = 4, will be between x = 0.5 and 1. Try x=0.8! It's pretty close to the right answer.

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