Posted by **Merisa Ann--Desperate for help!!** on Saturday, February 17, 2007 at 9:23am.

I need help with this problem.

The electricity meter on Donna's house

read 71,236.4 kwh at the beginning of

March and 73,196.2 kwh at the end of

March. She pays 7.4% per kwh.

What is the amount of her electricity

bill for March? Round to the nearest cent.

Do I add the kwh's used and divide 7.4?

Please help. Not sure how to work this,

and round to the nearest cent.

Subtract the initial from the final kwh readings to get the amount consumed for the month: 1958.8 kwh. The cost per kwh is 7.4 cents, NOT 7.4%. (That is a pretty low rate nowadays). The product of the amount consumed and the rate is $145.03 (after converting cents to dollars and rounding to the nearest cent)

which tool should be used to measure the mass of a bag of apples?

thermometer

inch ruler

produce scale

measuring cup

Take a wild guess. This is not a hard question.

thermometer duh

## Answer This Question

## Related Questions

- Math Please check - The electricity meter on Donna's house read 71,236.4 kwh at ...
- Math - The amount of a monthly electric bill (B, measured in $) depends on the ...
- phyical science - A microwave oven has a power requirement of 1235 W. A frozen ...
- math - In a normal month you use 1200 kWh of electricity. Your electricity ...
- Algebra 1- Please help whenever you get the chance - The monthly cost of ...
- Math - The “Limited Plan” offers a 15% discount for power usage between 7pm – ...
- GCSE Physics - The energy value of gas used in a home is measured in KWH. The ...
- consumer math - If you used 648 KWH and the power company charges 0.05954/KWH ...
- physics - How many kWh of energy would be needed for brushing your teeth with an...
- Chemistry - How many watts are in a kWh? Or how do you convert 30 kWh into ...

More Related Questions