Posted by **winterWX** on Friday, February 16, 2007 at 4:31pm.

A orbiting satellite stays over a certain spot on the equator of (rotating) Earth. What is the altitude of the orbit (called a "synchronous orbit")?

Write the equation for the period of a satellite in terms of the distance from the Earth's center. It is a special form of Kepler's Third law. Then set the period equal to 24 hours and solve for the distance from the center. Subtract the Earth's radius to get the altitude.

This reference may help:

http://www.ctiinfo.com/SatControl/ComTrack/InclinedOrbitTutorial/satgeom1.htm
ok thanks.

## Answer this Question

## Related Questions

- physics - A orbiting satellite stays over a certain spot on the equator of (...
- Physics - A orbiting satellite stays over a certain spot on the equator of (...
- Physics - A orbiting satellite stays over a certain spot on the equator of (...
- Physics-Gravity - A orbiting satellite stays over a certain spot on the equator ...
- Physics....Orbiting Satellite - A orbiting satellite stays over a certain spot ...
- physics - A satellite of mass 205 kg is launched from a site on Earth's equator ...
- Physics - A satellite of mass 220 kg is launched from a site on Earth's equator ...
- Physics - A satellite of mass 210 kg is launched from a site on Earth's equator ...
- physics - Two Earth satellites, A and B, each of mass m, are to be launched into...
- physics - Two Earth satellites, A and B, each of mass m, are to be launched into...

More Related Questions