Thursday

April 24, 2014

April 24, 2014

Posted by **soojung** on Friday, February 16, 2007 at 3:54pm.

You need to look up the half life of Sr-90 and also calculate the initial decay rate of 5.0 kg. The number or Sr-90 atoms initially is

(Avogadro's #)*(5000 g/89.9 moles/g) =

3.35*10^25 atoms.

The half life (from a handbook) is

T1/2 = 28 years = 8.84*10^8 s.

The decay constant is

lambda = 0.693/T1/2 = 7.84*10^-10 s^-1

The initial decay rate is therefore

(3.35*10^25) x (7.84*10^-10) =

2.6*10^16 counts/s

The time required for that to decay to 10 counts/s can be computed from the exponential decay law.

10 = 2.6*10^16 * e(-lambda*t)

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