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April 18, 2014

Homework Help: molarity

Posted by christine on Friday, February 16, 2007 at 12:54pm.

An aspirin tablet weighing 0.475 g has been analyzed and contains 68.2 % ASA (180.16 g/mol) by mass. A student dissolved
the tablet in hot NaOH and the cooled solution was diluted with DI water to the mark in a 250 mL volumetric flask. Exactly 3.00 mL
of the solution was pipetted into a 100 mL volumetric flask and diluted to the mark with FeCl3 solution.
The concentration of the diluted solution is ?
M.

You don't say concentration of what. or in what units? I assume you mean the concentration of ASA.
Mass ASA in the 250 mL flask was 0.475*0.682 = ??g

Then 3.00 mL was taken and diluted to 100 mL. The mass in the 100 mL flask is
??g x 3.00/250 = xx grams ASA.

If you want the concentration in g/mL it is xx g/100 mL.

If you want it in mols/L, then convert grams in the 100 mL flask to mols and divide by liters (0.1 L).

Post your work if you get stuck.

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