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September 17, 2014

September 17, 2014

Posted by **Robert** on Friday, February 16, 2007 at 11:43am.

x->0

This reads:

The limits as x approaches zero is (1 plus x) to the 1 divided by x.

The log of each term is

(1/x) ln (1 + x) = ln (1+x)/x

Using L'Hopital's rule for the limit of

f(x)/g(x), the limit if the log is

lim f'/g' = lim [1/(1+x)]= 1

and the antilog of that is e. 2.71828...

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