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March 29, 2015

March 29, 2015

Posted by **Robert** on Friday, February 16, 2007 at 11:38am.

s=4(sqroot t)+(3/t)+2t^5

This reads (4 times the square root of t) plus (3 divided by t) plus 2t to the 5th.

Differentiate it one term at a time, using the rule:

d/dt(t^n) = n*t^(n-1)

s(x) = 4 t^(1/2) + 3 t*(-1) + 2 t^5

ds/dx = 2/t(1/2) - 3/t^2 + 10 t^4

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