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August 29, 2014

August 29, 2014

Posted by **Dave** on Thursday, February 15, 2007 at 10:14pm.

2t^2+t-3, 2t^2+5t+3

I have 2t^2+t+3 as the LCM. Is this correct or can somebody step me through the correct method to complete the problem?

2t^2+t-3 = (2t+3)(t-1)

2t^2+5t+3 =(2t+3)(t+1)

Therefore (2t+3)(t-1)(t+1) is a multiple of both polynomials. It is also the Least Common Multiple

(2t+3)(t-1)(t+1) can be written as

(2t+3)(t^2-1)= 2t^3 +3t^2 -2t -3

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