# Algebra 2 -Conics

posted by
**Devyn** on
.

The directions are : Write each equation in standard form (if needed), then find appropriate information for the particular conic.

the question: y=2x^2-12x+19

HOW DO I BEGIN???

Complete the square and rewrite as

y = 2x^2-12x + 19

= 2(x^2 - 6x + 9)+ 19 - 18

= 2(x-3)^2 + 1

This is an upward-pointing parabola with its lowest point at x=3, y+1

If you define new coordinates as

y'= y-1 and x' = x-3,

the equation becomes

y' = 2 x'^2