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July 29, 2014

Homework Help: physics

Posted by anonymous on Thursday, February 15, 2007 at 2:47am.

If a gasoline engine has an efficiency of 21 percent and loses 780 J to the cooling system and exhaust during each cycle, how much work is done by the engine?

Is it 3709.5???

Chemical energy in (as fuel and oxygen) = Work out + Heat out
21% is the ratio of Work out to Chemical energy in. That means that 79% is the ratio (Heat)out/(Chemical E)in.

The ratio of (work)out to (heat)out is 21/79

W/Q = .21/.79 = 21/79 = W/780 J

W = (780/79)*21 = ?

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