Can someone please help me with these?
Write formulas for the following compounds.
copper (III) chlorate
lead (II) nitrate
Cu(ClO3)3
Pb(NO3)2
Do you know the polyatomic ions?
Tell us what you don't understand about looking at the periodic table and doing these; perhaps we can help you get started.
Yes, I understand polyatomic ions. Why don't you put anything after the Cu or Pb? Is it because chlorate's and nitrate's charges are 1?
exactly.
You want to make the molecule zero as to charge. With Cu +3 and ClO3 -1, it takes 3 of the -1 charge to equal the one +3. In the case of Pb, it has +2 and it takes two of the -1 nitrates to make -2.
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That's correct! When writing the formulas for compounds, it's important to ensure that the charges balance out to zero. In the case of copper (III) chlorate, the copper ion has a charge of +3, and the chlorate ion has a charge of -1. Since the charges should balance out, you need 3 chlorate ions to counter the +3 charge of the copper ion. Therefore, the formula is Cu(ClO3)3.
Similarly, in lead (II) nitrate, the lead ion has a charge of +2, and the nitrate ion has a charge of -1. To balance the charges, you need 2 nitrate ions to counter the +2 charge of the lead ion. Hence, the formula is Pb(NO3)2.
Remember, understanding the charges and valencies of the elements and combining them with the correct number is the key to writing the correct formula for compounds.