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April 19, 2014

April 19, 2014

Posted by **jasmine20** on Tuesday, February 13, 2007 at 1:01pm.

solve the system by subtraction.

5x-3y=13

4x-3y=11

equation#2 woudl be

4x-3y=11

-3y = -4x+11

y = (4)/(3) x - (11)/(3)

so now i substitute it to equation #1

5x - 3((4)/(3)x - (11)/(3)= 13

5x - 4 x +11 = 13

1x + 11 = 13

1x = 13-11

1x= 2

x = 2

now i substitute back into equation #1

5(2)-3y=13

10-3y=13

-3y = 13-10

-3y=3

y=-1

so , my solution would be (2,-1)

am i correct?

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