Homework Help: Calculus II

Posted by Shelley on Saturday, February 10, 2007 at 11:21pm.

Hello! I have a problem on volumes but I am having trouble visualizing the object.

y=ln(x), y=1, y=2, x=0, about the y-axis

For the graph, I graphed y=ln(x), then I have from 1 to 2. Is this one with a washer where I have integral fom 1 to 2 of pi*ln(x)^2 - pi* something?

I'm not so sure where to go after graphing it. It looks like an undefined area because there is no x-limit.

Thanks for your help.

The limit of x is determined by y=2 (y= ln(x) ) or x= e^2 at end

I would have integrated the volume as dy*PI radius^2 where radius is rad=e^y

check my thinking.

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