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The perimeter of a rectangle is 68 f. Find the dimensions of the rectangle if the ratioof the length to the width is 9:8

I am sorry that nobody has responded earlier.

The perimeter is the sum of the length of the four sides. Therefore:

2(9X) + 2(8X) = 68

Solve for X. Then 9X and 8X will give you the dimensions.

I hope this helps. Thanks for asking.

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