Fx = d(x) * q(x) + r(x)
if r cant be o and d(x) = 2 what is r?
To solve the equation Fx = d(x) * q(x) + r(x) for the value of r, we need more information. The equation will have different solutions depending on the specific values of Fx, q(x), and the values of x.
However, if we know that d(x) = 2 and r(x) cannot be equal to zero, we can simplify the equation further. Plugging in d(x) = 2, the equation becomes:
Fx = 2 * q(x) + r(x)
Since r(x) cannot be zero, we can infer that r(x) must be a non-zero constant. Specifically, r(x) ≠ 0. Therefore, r(x) can take any non-zero value.