Posted by **Marisol** on Friday, February 9, 2007 at 9:13am.

Consider the following gas phase reaction: 3A(g)+ 2B(g) <==> 1C(g)+4D(g). At 181.1C, Kp=270.91. Calculate Kc under these conditions.

My answer:

change of n = (1+4)-(3+2)=0

kp=kc(RT)^(change of of n)

207.91=kc(.0821)(454.1)^0

Therefore,

kc=270.91

Is this correct?

yes, Kp=Kc because delta n = 0

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