Posted by
**thomas** on
.

Can someone explain to me how to find the equation pf the line in the form Ax + By + C =0 if

a) parallel to x=3 and passes through (-4, 3)

b)perpendicular to y=4 and passes through (1, 1)

c) passes through the x-int of y=2x-6 and y-int of y=-3x+6

If it is parallel to x=3, the slope is undefined (vertical line), so it is an x=constant, in this case, x=-4

A=1, B=0, C=4

If it is perpendicular to y=4, then it is a vertical line. X=1

A=1 B=0, C=-1

2*3