Posted by **thomas** on Thursday, February 8, 2007 at 8:20pm.

Can someone explain to me how to find the equation pf the line in the form Ax + By + C =0 if

a) parallel to x=3 and passes through (-4, 3)

b)perpendicular to y=4 and passes through (1, 1)

c) passes through the x-int of y=2x-6 and y-int of y=-3x+6

If it is parallel to x=3, the slope is undefined (vertical line), so it is an x=constant, in this case, x=-4

A=1, B=0, C=4

If it is perpendicular to y=4, then it is a vertical line. X=1

A=1 B=0, C=-1

2*3

## Answer This Question

## Related Questions

- geometry - I would love for someone to check my work on the seven problems that ...
- math - i have more than one question so if u no any of the answers please tell ...
- Math - 1. What is the equation in standard form of a perpendicular line that ...
- Analytic Geometry - A line Q has an equation of x+5y+5=0. Find the equation of ...
- Analytic Geometry - A line Q has an equation of x+5x+5=0. Find the equation of ...
- Math -Quadratics Help! - I have a test tomorrow with a few sample questions that...
- Math - Quadratics & Analytical Geometry - I have a test tomorrow with a few ...
- Algebra 1 ( bobpursley) - 1. Write an equation in slope-intercept form for the ...
- algebra - given point slope form linear equation to use in answers y-3=3(x+ 1) a...
- Algebra - 1.Write an equation in slope- intercept form of the line that passes ...

More Related Questions