Sunday

November 23, 2014

November 23, 2014

Posted by **Shelley** on Thursday, February 8, 2007 at 5:25pm.

1. Sketch the region in the xy-plane defined by the inequalities x-2(y^2)> 0 and 1-x-abs(y)>0. and find its area.

Would it be best to solve for x, then graph it as x= something? Then find the integral with dy?

2. a. Find the number a such that the line x=a bisects the area under the curve y=1/x^2, 1<x<4.

b. Find the number b such that the line y=b bisects the area in part a.

For this, I graphed it then tried to draw a line to vertically bisect it. Is it right to just say that b is the x value that it bisects the graph at?

Thank you for your help!!

Yes, I would do the first one that way.

Yes, but you can do it with the integral, let the integral of one side equal the integral of the other side, then solve for b, the center part.

**Answer this Question**

**Related Questions**

Algebra - Consider the two inequalities 2x - 4 < y and y < -2/3x + 2. (b) ...

Systems of Inequalities-8th Grade Algebra - Graph the equation. The graph will ...

Calculus AB - Consider the region bounded by the graphs of the equations x=y^2 ...

Calculus - MathMate Please help - ok, i tried to do what you told me but i cant ...

algebra1 - graph the system of inequalities, and classify the figure created bu ...

algebra1 - graph the system of inequalities, and classify the figure created bu ...

double integrals - Combine the following two integrals into one by sketching the...

Calculus (Definite Integrals) - How many definite integrals would be required to...

Calculus please help!!! double integral - Combine the following two integrals ...

Algebra - Solve the following linear inequality graphically. x+2y<4 x-y<5 ...