posted by **chocolatekisses on .
A 35-kg skier skis directly down a frictionless slope angled at 11° to the horizontal. Assume the skier moves in the negative direction of an x axis along the slope. A wind force with component Fx acts on the skier. What is Fx (in N) if the magnitude of the skier's velocity is.. constant? ..increasing at a rate of 1.0 m/s^2? ..increasing at a rate of 2.0 m/s^2?
Writing the sum of the forces down the slope....
In the first part, a=0
and solvee for Fx?
.. as for the increasing rate.. is it telling me that the 1.0m/s2 is added to the gravity of 9.8m/s2?
this is kinda late answer, but still...
This works for a = 0
More complete answer... (a!=0)
So, for increasing rate of a = 1m/s^2
This is going in negative direction, so
And for a = 22/s^2
Crunch in calculator for Fx in Newtons
Actually, just noticed that was for in -x direction, so change sign on acceleration
ur supposed to multiply the 35sintheta with the acceleration due to gravity (9.8)