Tuesday
July 22, 2014

Homework Help: physics

Posted by **chocolatekisses on Thursday, February 8, 2007 at 5:14pm.

A 35-kg skier skis directly down a frictionless slope angled at 11 to the horizontal. Assume the skier moves in the negative direction of an x axis along the slope. A wind force with component Fx acts on the skier. What is Fx (in N) if the magnitude of the skier's velocity is.. constant? ..increasing at a rate of 1.0 m/s^2? ..increasing at a rate of 2.0 m/s^2?

Writing the sum of the forces down the slope....

Weight*sinTheta-Windfriction=mass*acceleration.

In the first part, a=0



so..

35*sin(11)-Fx=0

and solvee for Fx?


.. as for the increasing rate.. is it telling me that the 1.0m/s2 is added to the gravity of 9.8m/s2?

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

physics - A 48 kg skier skis directly down a frictionless slope angled at 5 to ...
college level physics - a 40 kg skier skis down a frictionless slope angled at ...
physics - A skier with a mass of 70 kg starts from rest and skis down an icy (...
Physics - A skier with a mass of 56 kg starts from rest and skis down an icy (...
Physics - A skier with a mass of 66.6 kg starts from rest and skis down an icy (...
Physics - A ski slope drops at an angle of 24 degrees with respect to the ...
physics - A 40 kg skier comes directly down a frictionless ski slope that is ...
Physics - A skier squats low and races down a 14 degree ski slope. During a 5 s...
physics - A 40 kg skier comes directly down a frictionless ski slope that is ...
physics - A skier squats low and races down an 11◦ ski slope. During a 3 s...

Search
Members