I would like my equation checked, sodium cyanide and water.I have worked the balanced equation as: NaCN+H20=NaOH+HCN.
If you want the molecular equation this looks good to me. Actually, it's the CN^- that is hydrolyzed (reacts with water) and the ionic equation is
CN^- + HOH ==> HCN + OH^-
In the old days they called this hydrolysis. Now the line is that this is a Bronsted-Lowry acid/base reaction and CN^- is a stronger base (proton acceptor) than H2O and pulls a H^+ away from water.
What happens to the Na during hydrolysis