Posted by **Emily** on Wednesday, February 7, 2007 at 10:50pm.

Ok, I am supposed to find out what the variables are by factoring and finding square roots. I couldn't find the right factors of a and c that added up to b in the equation (did that make sense?). Please help me find them! TYVM

-5n+6n^2-4=0

6y^2+12y+13=2y^2+4 simplified is:

4y^2+12y+9=0.

I know the answer to the second equation is -3/2, so I know it is a binomial square we are dealing with. Plz help, any help is greatly appreciated!

-5n+6n^2-4=0 or

6n^2-5n-4=0 does it factor to

(3n -4)(2n+ 1)

4y^2+12y+9=0.

(2y+3)^2

The first equation is -5n+6n^2-4, not 6n^2-5n-4=0. Thnx for all your help!!

- Quadratic Equations -
**mani**, Tuesday, April 2, 2013 at 12:51pm
the roots of the equation are

n=[(-b)+sqrt(b^2-4*a*c)]/2*a

n=[(-b)-sqrt(b^2-4*a*c)]/2*a

thus,

n=[5+sqrt(25+96)]/2*6

n=[5-sqrt(25+96)]/2*6

so,the values of n for this eqn. are

n=4/3,-1/2

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