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December 20, 2014

December 20, 2014

Posted by **Issac** on Wednesday, February 7, 2007 at 5:43pm.

My answer is 267.03.

2. The half-life of a second-order reaction is 2.508 days. How many days will have elapsed after 8 half-lives?

My answer is 5.330.

Is this correct or did I do it wrong?

PLEASE HELP ME!!!!

The first one is ok except you have only three signifant figures so you should report to 267.

I don't get your answer for #2. For a second order reaction, The first half life occurs at 2.508 days. The second half life is 2x that or 5.016 days, the third half life is 4x that or 10.032 days etc.

- half-life -
**Jeje**, Tuesday, October 22, 2013 at 10:45amRn-222 has a half-life of 3.82 days. How long before only 1/16 of the original sample remains?

Solution:

recognize 1/16 as a fraction associated with 4 half-lives (from (1/2)4 = 1/16)

3.82 days x 4 = 15.3 days

- half-life -
**Jeje**, Tuesday, October 22, 2013 at 10:46amU-238 has a half-life of 4.46 x 109 years. Estimates of the age of the universe range from 9 x 109 years to 23 x 109 years (Cauldrons in the Cosmos: Nuclear Astrophysics, C.E. Rolfs and W.S. Rodney, Univ. of Chicago, 1988, p. 477). What fraction of this isotope present at the start of the universe remains today? Calulate for both minimum and maximum values, as well as a median value of 16 x 109 years.

Solution:

1) Calculation for the median value:

(16 x 109) / (4.46 x 109) = 3.587 half-lives

2) What fraction remains?

(1/2)3.587 = 0.0832

8.32% remains

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