# chemistry

posted by
**Rob**
.

Consider the equilibrium, A + B <--> C, with K=32.217 and initial concentrations of A,B, and C, of 3.665M, 0.883M, and 3.925M, respectively. What is the equilibrium concentration of B

3.665 0.883 3.925

A + B = C

Keq=(C)/(A)*(B)= 32.217

Q = (3.025)/(3.665)*(0.883)=1.21

Q < Keq; therefore, the reaction must proceed to the right.

Let y = amount of C formed.

At equilibrium,

(A) = 3.665-y

(B) = 0.883-y

(C) = 3.925+y)

Solve for y and the concentration of each. Post your work if you get stuck.