Posted by **Susane** on Tuesday, February 6, 2007 at 10:13pm.

A nylon string has a linear density of 7.2g/m and is under a tension of 150N. The fixed supports are 90cm apart. The string is oscillating in the standing wave pattern. Find a)speed b)wavelength c) frequency

v=sqr(F/u(linear density)

v=sqrt(150N/7.2g/m)

= 4.56m/s

b) wavelength = 2L/3

= .6

The formular is =2L/n

n= nodes. The pictures shows three nodes in the standing wave pattern.

c) v= wavelength * frequency

4.56=.6 *f

f=7.6 Hz

Shouldn't linear density be changed to kg/m when determining velocity?

Wavelength should be twice the 90cm, shouldn't it? The end points determine the nodes, and between nodes it should be 1/2 wavelength.

wavelength= 2(.9m) I don't know why you chose n=3, I would have thought n=1 for the fundamental.

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