I need help in drawing a structual formula for hydrogen cyanide(HCN)and cyanogen(CN)2, the drawing has to bear in mind the valencies of hydrogen(1),nitrogen(3) and carbon (4), any help appreciated
H:C:::N:
:N:::C:C:::N:
Check my thinking. The previous one, too.
To draw the structural formula for hydrogen cyanide (HCN), you need to consider the valencies of hydrogen, nitrogen, and carbon.
Start by placing the carbon atom in the center since carbon typically forms four bonds. Then, attach the hydrogen atom to the carbon atom, bearing in mind that hydrogen forms only one bond. Finally, connect the nitrogen atom to the carbon atom, making sure to fulfill the nitrogen atom's valency of three bonds.
The structural formula for hydrogen cyanide (HCN) should look like this:
H:C≡N:
Now, let's move on to drawing the structural formula for cyanogen (CN)2.
Since cyanogen consists of two cyanide ions (CN-), we can redraw the structure by combining two cyanide units.
Start by drawing one cyanide unit as we did for hydrogen cyanide (HCN), with carbon in the center, hydrogen attached to carbon, and nitrogen connected to carbon.
The structural formula for one cyanide unit (CN-) is:
:C≡N:
To draw cyanogen (CN)2, simply attach two cyanide units together by sharing a nitrogen atom. Connect the two carbon atoms from each cyanide unit to the shared nitrogen atom.
The structural formula for cyanogen (CN)2 should look like this:
:N≡C:C≡N:
I hope this explanation helps you draw the structural formulas correctly.