how do i simplify comlex fractions, like this one:
((5/x)-(x/x-1)) / ((x/x+1)+(6/x))
These are strains...you strain.
Start with the numerator
((5/x)-(x/x-1))
Multply by x(x-1)/x(x-1)
That simplifies it some.
Then the denominator:
multiply be x(x-1)/x(x-1)
See if that gets you somewhere. WATCH signs.
if iadd the square of a number to 2 times the number, i get 63. what could the number be?
i need help wit roman numerals asap
To simplify complex fractions, you can follow these steps:
Step 1: Start with the numerator and simplify it first. In this case, the numerator is ((5/x)-(x/x-1)).
Step 2: Find a common denominator for the fractions within the numerator. In this case, the common denominator is x(x-1) because it is the least common multiple of x and x-1.
Step 3: Multiply each fraction in the numerator by x(x-1)/x(x-1) to eliminate the denominators. This results in (5(x-1)/(x(x-1)) - (x^2/(x(x-1))).
Step 4: Simplify the numerator by combining like terms. 5(x-1) - x^2 becomes 5x-5 - x^2.
Step 5: Move on to the denominator, ((x/x+1)+(6/x)).
Step 6: Utilize the same process as before and find a common denominator, which is x(x+1) in this case.
Step 7: Multiply each fraction in the denominator by x(x+1)/x(x+1) to eliminate the denominators. This results in (x(x+1)/(x(x+1)) + 6(x+1)/(x(x+1))).
Step 8: Simplify the denominator by combining like terms. x(x+1) + 6(x+1) becomes x^2 + x + 6x + 6.
Step 9: Now that both the numerator and denominator have been simplified, you can write the complex fraction as a single fraction by dividing the numerator by the denominator: (5x-5 - x^2) / (x^2 + x + 6x + 6).
To find the value of x in the equation x^2 + 2x = 63, you can follow these steps:
Step 1: Rewrite the equation as x^2 + 2x - 63 = 0. This is a quadratic equation.
Step 2: Attempt to factor the quadratic equation to find its roots. In this case, the equation factors as (x - 7)(x + 9) = 0.
Step 3: Set each factor equal to zero and solve for x. x - 7 = 0 or x + 9 = 0. These equations give x = 7 or x = -9.
Therefore, the potential values of x that satisfy the equation x^2 + 2x = 63 are x = 7 and x = -9.
If you need help with Roman numerals, please let me know specifically what you need assistance with, and I'll be happy to explain it to you.