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Tuesday, February 6, 2007
(-2x^2y)^3*(5xy^3)^2=(-2x^2y)^3 = -8 x^6 y^3
*Please check my work.
What did you do with the (5xy^3)^2 part. The first part you did ok. But you can't just throw away part of the equation.
I don't get that part.What do I do there.?
You did the first part ok by cubing it. I don't understand why you didn't do this part and square it. Such is life, I guess.
then I just multiply right.?
ok so will it be:-200x^8y^9
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