Tuesday

October 21, 2014

October 21, 2014

Posted by **jasmine20** on Monday, February 5, 2007 at 9:10pm.

The length of a rectangle is 2in. more than twice its width. If the perimeter of the rectangle is 34 in., find the dimensions of the rectangle.

Let L = length and W = width.

L = 2W +2

The perimeter of a rectangle is given by:

P = 2L + 2W Substitute L = 2W +2 and P = 34 then solve for W.

34 = 2(2W + 2) + 2W Simplify.

34 = 6w + 4 Subtract 4 from both sides.

30 = 6w Divide both sides by 6

W = 5

L = 2w + 2 = 2(5) + 2 = 10 + 2 = 12

The dimensions of the rectangle are:

Length = 12 inches and the width = 5 inches.

WOW. Excellent work. Geepers, you are headed to be a tutor here in a few years.

**Answer this Question**

**Related Questions**

math,algebra - Can someone help me just to do the setup of this the two ...

math - a rectangle is twice as long as it is wide. if both of its dimensions are...

algebra , help - Can someone help me set up the equations thanks. Directions: ...

MATH0098 - The length of a rectangle is 3ft more than twice its width, and the ...

math - an architect wants to draw a rectangle with a diagonal of 13 inches.the ...

Algebra - How do I solve this? The perimeter of a rectangular writing pad is 28 ...

MATH,CORRECTION - Directions solve each of the following problems. Besure to ...

Basic Algebra - The width of a rectangle is x inches long. The length of that ...

algebra - the width of a rectangle is 3 less than twice the length of x. if area...

ALGEBRA WORD PROBLEM! HELP! - And if a length of a rectangle is 3 more than ...