Posted by **jasmine20** on Monday, February 5, 2007 at 9:08pm.

Directions solve each of the following problems. Besure to show the equation used for the solution.

In a town election, the winning candidate had 220 more votes than the loser. If 810 votes were cast in all, how many votes did each candidate received?

answer:

Let x = the number of votes received by the losing candidate, then the winning candidate received x + 220 votes. The sum of these two amounts equal 810.

Equation:

X+(x +200)=180 simplify & solve for x.

2x+220=810 subtract 220 from both sides.

2x = 590 divide both sides by 2

X = 295

The losing candidate received 295 votes.

The winning candidate received 295 + 220 = 515 votes.

correct. You can generally check these your self by going back to the original problem statement.

total= one candidate + other candidate

= 295 + 295 + 220 = 810

## Answer This Question

## Related Questions

- math - In a town election the winning candidate had 220 more votes that the ...
- ALGEBRA - In a town election, the winning candidate had 220 more votes than the ...
- Algebra - In an election between two candidates, 530 votes were cast. If the ...
- math - In an election for a town mayor there were three candidates A,Band C the...
- Math - In a special local election, one candidate received 288 votes less than ...
- Math - In an election of two candidates the successful candidate secured 236 ...
- maths - At an election, a candidate secures 40% of the total votes but is ...
- math - A polling company took 5 polls in the week before and election. It showed...
- ratios/algebra - During class elections 64 students voted for candidate A .if ...
- Algebra - In a recent school board election, the two candidates for president ...

More Related Questions