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April 20, 2014

April 20, 2014

Posted by **jasmine20** on Monday, February 5, 2007 at 9:08pm.

In a town election, the winning candidate had 220 more votes than the loser. If 810 votes were cast in all, how many votes did each candidate received?

answer:

Let x = the number of votes received by the losing candidate, then the winning candidate received x + 220 votes. The sum of these two amounts equal 810.

Equation:

X+(x +200)=180 simplify & solve for x.

2x+220=810 subtract 220 from both sides.

2x = 590 divide both sides by 2

X = 295

The losing candidate received 295 votes.

The winning candidate received 295 + 220 = 515 votes.

correct. You can generally check these your self by going back to the original problem statement.

total= one candidate + other candidate

= 295 + 295 + 220 = 810

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