Sunday

December 21, 2014

December 21, 2014

Posted by **jasmine20** on Monday, February 5, 2007 at 9:08pm.

In a town election, the winning candidate had 220 more votes than the loser. If 810 votes were cast in all, how many votes did each candidate received?

answer:

Let x = the number of votes received by the losing candidate, then the winning candidate received x + 220 votes. The sum of these two amounts equal 810.

Equation:

X+(x +200)=180 simplify & solve for x.

2x+220=810 subtract 220 from both sides.

2x = 590 divide both sides by 2

X = 295

The losing candidate received 295 votes.

The winning candidate received 295 + 220 = 515 votes.

correct. You can generally check these your self by going back to the original problem statement.

total= one candidate + other candidate

= 295 + 295 + 220 = 810

**Answer this Question**

**Related Questions**

math - In a town election the winning candidate had 220 more votes that the ...

ALGEBRA - In a town election, the winning candidate had 220 more votes than the ...

Math - In a special local election, one candidate received 288 votes less than ...

Math - In an election of two candidates the successful candidate secured 236 ...

math - A polling company took 5 polls in the week before and election. It showed...

Math - A survey of 1000 registered voters revealed that 450 people would vote ...

math, HELP ME PLEASE! - A polling company took 5 polls in the week before an ...

math ,correction - Directions: Solve each of the following problems. Be sure to ...

Math - If each voter voted for only one candidate what is the fewest number of ...

Math - Nash equilibrium - Part 1 Consider a variant of electoral competition on ...