Use the Substitution method to solve the system of equations.

y - 2x = -5
3y - x = 5

Solve one of the equations for x or y.

Let's solve the first one for y:
y - 2x = -5
y = 2x - 5

Now let's substitute 2x - 5 for y in the second equation to solve for x:
3(2x - 5) - x = 5
6x - 15 - x = 5
5x - 15 = 5
5x = 20
x = 4

Substitute 4 for x in either equation to solve for y. Let's choose the first one.
y - 2(4) = -5
y - 8 = -5
y = 3

There you have it! Check the solution with both equations to make sure we have the right solutions. It always helps to check your work!

I hope this will help.

6 answers

mathway.com is a big help

How will I solve the substitutions of simultaneous equation of ×+y=4

2×-y=5

To solve the system of equations using the Substitution method, you start by solving one of the equations for either x or y. In this case, let's solve the first equation for y.

First equation: y - 2x = -5

By isolating y, we can rewrite this equation as y = 2x - 5.

Now that we have a value for y in terms of x, we can substitute it into the second equation.

Second equation: 3y - x = 5

Replace y with 2x - 5:

3(2x - 5) - x = 5

Now simplify the equation:

6x - 15 - x = 5

Combine like terms:

5x - 15 = 5

Next, solve for x:

5x = 20

Divide both sides by 5:

x = 4

Now that we have the value of x, we can substitute it back into the first equation to find the value of y.

y - 2x = -5

Replace x with 4:

y - 2(4) = -5

Simplify:

y - 8 = -5

Add 8 to both sides:

y = 3

So the solution to the system of equations is x = 4 and y = 3.

To double-check your answer, you can substitute these values back into both original equations to see if they satisfy both equations.

Yes

Solve :4g-6h-5g-3g+10h+6g

2m+n=0

M+2n=3