x+1 -x+2 = x+3
____ _____ ____
2 3 4
How do I solve this equations? These are fractions
mi don't know
I'm going to assume your problem is this:
(x+1)/2 - (x+2)/3 = (x+3)/4
...and you are trying to solve for x.
If so, here's how you would go about it:
First, get rid of the fractions. Let's multiply every term by 12.
12 [(x+1)/2 - (x+2)/3 = (x+3)/4]
6(x+1) - 4(x+2) = 3(x+3)
This is now easier to solve for x.
Working this out:
6x + 6 - 4x - 8 = 3x + 9
2x - 2 = 3x + 9
-11 = x
Substitute -11 for x in the original equation to check. It always helps to check your work!
I hope this helps and is what you were asking.
To solve the equation, you can follow these steps:
1. Start by simplifying both sides of the equation by multiplying each term by the least common multiple (LCM) of the denominators (2, 3, and 4). In this case, the LCM is 12.
Multiply the numerators by the corresponding factor to get rid of the fractions.
12[(x + 1)/2 - (x + 2)/3 = (x + 3)/4]
Simplifying, we get:
6(x + 1) - 4(x + 2) = 3(x + 3)
2. Distribute the coefficients to eliminate the parentheses.
6x + 6 - 4x - 8 = 3x + 9
3. Combine like terms on both sides.
2x - 2 = 3x + 9
4. Move all terms with x to one side of the equation.
Subtract 3x from both sides:
2x - 3x - 2 = 3x - 3x + 9
Simplifying, we get:
-x - 2 = 9
5. Isolate x by moving the constant terms to the other side.
Add 2 to both sides:
-x - 2 + 2 = 9 + 2
Simplifying, we get:
-x = 11
6. To solve for x, multiply both sides by -1 to get rid of the negative sign in front of x.
-1(-x) = 11(-1)
Simplifying, we get:
x = -11
So the solution to the equation is x = -11.