posted by anonymous .
The (aq) solution with the lowest freezing temperature would be which of the following:
The NaCl and the NaNO3 break up into two particles each. The sugar does not, and the acetic acid hardly ionizes at all.
That changes the concentration of dissolved particles to..
So the answer is: Which has the higher concentration of particles?
is it 0.060M NaNO3 because it has the higher concentration of particles?