Posted by **COFFEE** on Saturday, February 3, 2007 at 10:53pm.

Two horizontal forces act on a 2.4 kg chopping block that can slide over a frictionless kitchen counter, which lies in an xy plane. One force is F1 = (3.4 N) i + (3.7 N) j. Find the acceleration of the chopping block in unit-vector notation for each of the following second forces:

F2 = (-3.4 N) i + (-3.7 N) j

F2 = (-3.4 N) i + (3.7 N) j

F2 = (3.4 N) i + (-3.7 N) j

In vector notation;

Force= mass*acceleration

acceleration= Force/mass

add the vector forces, divide bymass

example, the last:

Ftotal=F1 + F2

= 3.4 i + 3.7 j + 3.4i - 3.7 j

= 6.8 i

acceleration= 6.8/2.4 i

## Answer this Question

## Related Questions

- AP Physics - While two forces act on it, a particle is to move at the constant ...
- Physics - Block B has a mass of 4.2 kg and block A has a mass of 2.6 kg. They ...
- Physics - A block of mass m lies on a rough plane which is inclined at an angle...
- Math/Physics2 - The block has mass m=8.5 kg and lies on a fixed smooth ...
- Physics - Two horizontal forces F1 and F2 act on a 1.7 kg disk that slides over ...
- Physics - Starting from rest, a 4-kg block slides 10 m down a frictionless 30 ...
- physics - A block of mass 39 kg lies on an inclined plane, as shown. The ...
- physics - A force of 8.7 N is applied to a steel block initally at rest on a ...
- physics - The initial velocity of a 2.36 kg block sliding down a frictionless ...
- physics - Two forces, of magnitudes F1= 80.0N and F2= 50.0N, act in opposite ...

More Related Questions