Physics
posted by COFFEE on .
Two horizontal forces act on a 2.4 kg chopping block that can slide over a frictionless kitchen counter, which lies in an xy plane. One force is F1 = (3.4 N) i + (3.7 N) j. Find the acceleration of the chopping block in unitvector notation for each of the following second forces:
F2 = (3.4 N) i + (3.7 N) j
F2 = (3.4 N) i + (3.7 N) j
F2 = (3.4 N) i + (3.7 N) j
In vector notation;
Force= mass*acceleration
acceleration= Force/mass
add the vector forces, divide bymass
example, the last:
Ftotal=F1 + F2
= 3.4 i + 3.7 j + 3.4i  3.7 j
= 6.8 i
acceleration= 6.8/2.4 i

a = (F1 + F2) / m
where a, F1, & F2 are in vector notation