Posted by **Troyyyy** on Saturday, February 3, 2007 at 3:58pm.

the velocity of the wind would be:

(42km/h)cos(30)=36.37

After flying for 15 min in a wind blowing 42 km/h at an angle of 30° south of east, an airplane pilot is over a town that is 50 km due north of the starting point. What is the speed of the airplane relative to the air in km/h?

what formula do u start with?

## Answer This Question

## Related Questions

- Physics/Math - After flying for 15 min in a wind blowing 42 km/h at an angle of ...
- physics - After flying for 13 min in a wind blowing 44 km/h at an angle of 21° ...
- Physics - After flying for 15 min in a wind blowing 42 km/h at an angle of 28° ...
- physics - After flying for 13 min in a wind blowing 37 km/h at an angle of 25° ...
- Physics - After flying for 15 min in a wind blowing 42 km/h at an angle of 34° ...
- physics - After flying for 15 min in a wind blowing 42 km/h at an angle of 20° ...
- physics - After flying for 15 min in a wind blowing 42 km/h at an angle of 20° ...
- physics - After flying for 15 min in a wind blowing 42 km/h at an angle of 20° ...
- science - An airplane pilot sets a compass course due west and maintains an ...
- Physics I NEED HELP BADLY - An airplane traveling east at a speed of 270 km/h ...

More Related Questions