Posted by **MatT** on Friday, February 2, 2007 at 11:39am.

5uC charges are at the base vertices of an equilateral triangle 0.4m on a side. What is the electric field at the third vertice?

im not completely sure how to start that.. don't i need the force to calculate the x&y components?

NO. Figure E directly from a charge.

Everticalfrom one charge=k q/d^2 sin60

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