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November 27, 2014

November 27, 2014

Posted by **matt** on Thursday, February 1, 2007 at 9:07pm.

DUUUUUUUUUH!

THIS IS SO EASY!

LOOK IN YOUR BOK, IDIOTIC DUDE! R U A BOY AND HOT, HOTTIE SEEYA L8ER

thanks for your help ellie!

Yikes!

Sorry about the crazy response! It sure doesn't look like physics to me!

If you put each of the charges at the corners of equilateral triangles, then the angles are 60. Then, for each charge, you need to calculate the net electrical field that that charge feels. The sides are length r.

For example, consider triangle with q1 at lower left, q2 at top, and q3 at lower right.

the field felt by q1:

E net (x direction) = E2 (x direction) + E3 (x direction.

E net x = E2 cos60 + E3

= k/r^2 * q2cos60 + k/r^2 * q3

E net y = E2 (y direction + E3 (y direction)

E net y = E2 sin60 + 0

k/r^2 * q2sin60

Now you have the electrical field felt by q1.

To get the force, use F = qE

Hope this is a start for you!!

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