# Math

posted by
**DrBob222** on
.

3x-4 to y+15

is constant and

y=3 when x=2

then when

y=12, x equals?

My answer was 13. Im not sure how to solve this question. Could you please go through the steps so I can see they match up with mines.

My Steps:

3x-y:y+15 **The original problem above says 3x-4 and not 3x-y. Try it again. I have 7/3 for the answer.**

3x-12:12+15

3x-12:27

-12-27:-3x

-39:-3x

13:x

I'll try again:

3x-4:y+15

3x:12+15+4

3x:31

Now what. Is what I did right?

I need help with this problem.

Given that the ratio of

3x-4 to y+15

is constant and

y=3 when x=2

then when

y=12, x equals?

My answer was 13. Im not sure how to solve this question. Could you please go through the steps so I can see they match up with mines.

My Steps:

3x-y:y+15

3x-12:12+15

3x-12:27

-12-27:-3x

-39:-3x

13:x

The problem said the ratio was a constant when x=2 and y=3

I substituted x = 2 and y=3 and solved for the constant.

(3x-4)/(y+15) = k

I found 1/9 for k.

Then I started anew, substituted y=12 and solved for x.

There may be an easier way to do it but I think this will work.

I tried that did I not. I honestly don't understand. Can you please type it out.