Posted by **DrBob222** on Thursday, February 1, 2007 at 3:37pm.

3x-4 to y+15

is constant and

y=3 when x=2

then when

y=12, x equals?

My answer was 13. Im not sure how to solve this question. Could you please go through the steps so I can see they match up with mines.

My Steps:

3x-y:y+15

**The original problem above says 3x-4 and not 3x-y. Try it again. I have 7/3 for the answer.**
3x-12:12+15

3x-12:27

-12-27:-3x

-39:-3x

13:x

I'll try again:

3x-4:y+15

3x:12+15+4

3x:31

Now what. Is what I did right?

I need help with this problem.

Given that the ratio of

3x-4 to y+15

is constant and

y=3 when x=2

then when

y=12, x equals?

My answer was 13. Im not sure how to solve this question. Could you please go through the steps so I can see they match up with mines.

My Steps:

3x-y:y+15

3x-12:12+15

3x-12:27

-12-27:-3x

-39:-3x

13:x

The problem said the ratio was a constant when x=2 and y=3

I substituted x = 2 and y=3 and solved for the constant.

(3x-4)/(y+15) = k

I found 1/9 for k.

Then I started anew, substituted y=12 and solved for x.

There may be an easier way to do it but I think this will work.

I tried that did I not. I honestly don't understand. Can you please type it out.

## Answer this Question

## Related Questions

- college math - I do not understand a problem from a text book or how to solve ...
- Algebra - Re-write 2x - 3y ≤ 6 in slope-intercept format. I'm really not ...
- Science - I am reviewing for a test and I don't know how to attempt this ...
- Basic Math - I forgot how to solve for two variables... Please check if I solved...
- math - if (2x-3):(y+4)=k where k is a constant and x=4 when y=2 then find x when...
- Maths - i have an answer but im not sure if its right would you tell me please ...
- math - 1/4x-1/6y=-2 -1/6x+1/5y=4 solve for x and y its suppose to be x equals 12...
- Physics - I am reviewing for a test and I don't know how to attempt this ...
- Algebra - I was given an answer to a question but what I really need are the ...
- math:solving for an exponent. - I can't get the right answer, where am I going ...