Wednesday

April 16, 2014

April 16, 2014

Posted by **tyler** on Wednesday, January 31, 2007 at 10:08pm.

x divided by sqrt(x^2 + b^2) dx

im having a lot of trouble, thanks in advance

Let u = x^2 + b^2

du = 2x dx

The integrand becomes

(1/2) u^(-1/2) du

and the integral of this is u^(1/2)

= sqrt(x^2 + b^2)

Evaluate this between your limits.

First set u = x^2 + b^2

du = 2(x+b)or 2x + 2b

It would be very tedious to try to solve this on line with no signs for integral, radical, etc. But above is the first step to solving this problem. You must first find du. As you can see, you'll have some messy exponents to work with, something that would be very difficult to do here.

Is b a constant? This entire thing is crazy. Where is the dx?

If b is a constant,

du=2x dx

**Related Questions**

Calculus - I am having a lot of trouble doing these types of problems. Can ...

ap calculus - Which of the following definite integrals gives the length of y = ...

calc check: curve length - Find the length of the curve y=(1/(x^2)) from ( 1, 1...

calculus - There are four integrals: 1) definite integral x/(1+x^4)dx b/w ...

calculus - There are four integrals: 1) definite integral x/(1+x^4)dx b/w ...

Calc 2 - Evaluate the definite integral from 0 to 1 of (x^2)sqrt(5x+6)dx

Calc BC - 1. Find the indefinite integral. Indefinite integral tan^3(pix/7)sec^2...

math - I'm having trouble solving this problem: definite integral (2-t)(sqrt(t...

calc: arc length - find the exact length of this curve: y = ( x^3/6 ) + ( 1/2x...

Calculus - Evaluate the definite integral. dx/(x*sqrt(lnx)) from 1 to e^4 I'm ...