Posted by **chrisw** on Wednesday, January 31, 2007 at 7:15pm.

find 3 consecutive integers such that the product of the second and third integer is 20

Take three integers x, y, and z.

The for xyz, we want y*z = 20

The factors of 20 are

20*1

10*2

5*4.

20*1 are not consecutive.

10*2 are not consecutive.

But 5 and 4 are consecutive; therefore, we just add 3 in front to make it 345.

These are three consecutive integers and the second and third multiply to give 20.

n, n+1, n+2 are the integers.

(n+1)(n+2)=20

solve for n.

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