# quad. eq.

posted by
**chrisw**
.

find 3 consecutive integers such that the product of the second and third integer is 20

Take three integers x, y, and z.

The for xyz, we want y*z = 20

The factors of 20 are

20*1

10*2

5*4.

20*1 are not consecutive.

10*2 are not consecutive.

But 5 and 4 are consecutive; therefore, we just add 3 in front to make it 345.

These are three consecutive integers and the second and third multiply to give 20.

n, n+1, n+2 are the integers.

(n+1)(n+2)=20

solve for n.